√100以上 ¯ 40 ã ¯^ Y c[ ubN 310968
C) P(Y XjY 025) SOLUTION These problems are most easily solved by drawing pictures and computing the areas of the triangular regions that you see For part (a) the answer is 1 12(2)(3 4)(3 4) = 7 16 (we did this as an example in class) For part (b) the answer is 1 1 2 (1)(4 5) 1 2 (1)(3 4) = 9 40 For part (c), P(Y X;Y 024 c JFessler,May27,04,1310(studentversion) 212 Classication of discretetime signals The energy of a discretetime signal is dened as Ex 4= X1 n=1 jxnj2 The average power of a signal is dened as Px 4= lim N!1 1 2N 1 XN n= N jxnj2 If E is nite (E Nanocatalysts For Hydrogen Evolution Reactions Physical Chemistry Chemical Physics Rsc Publishing Doi 10 1039 C7cpd "'"¯ 40 'ã "¯^ "Y c[ ubN